I tried multiple times and got stupidly varied answers of having to dose from as much as 1616 Litres to as little as 16 microlitres of the ferts solution!
From my own workings out, I felt that the following exchange resulted in the most accurate answer.
Me
ChatGPTIf I add 50 grams of Potassium Nitrate to 2000ml of distilled water what will be the concentration of nitrate in the solution expressed as parts per million, using the molar mass of Potassium Nitrate to calculate this.
MeTo calculate the concentration of nitrate in the solution in parts per million (ppm), we need to first calculate the number of moles of potassium nitrate in the solution, and then use this to determine the concentration of nitrate ions.
The molar mass of potassium nitrate is 101.1032 g/mol (39.0983 g/mol for potassium and 14.0067 g/mol for nitrogen, plus 3 x 16.00 g/mol for oxygen).
To calculate the number of moles of potassium nitrate in 50 grams, we divide the mass by the molar mass:
moles of KNO3 = 50 g / 101.1032 g/mol = 0.494 moles
Next, we need to calculate the concentration of nitrate ions. Since each molecule of potassium nitrate contains one nitrate ion, the concentration of nitrate ions is equal to the concentration of potassium nitrate.
The volume of the solution is 2000 mL, or 2 L.
Concentration of KNO3 = moles of KNO3 / volume of solution = 0.494 moles / 2 L = 0.247 M
To convert the concentration to ppm, we need to multiply by the conversion factor 10^6 ppm / 1 M:
Concentration of KNO3 in ppm = 0.247 M x 10^6 ppm / 1 M = 247000 ppm
Therefore, the concentration of nitrate in the solution expressed as parts per million (ppm) is 247000 ppm.
ChatGPTHow much of the above solution would I need to add to 200 litres of distilled water to give it a nitrate concentration of 2ppm?
Would anyone with a a better understanding of this care to weigh in and confirm or correct this for me?To calculate the amount of the potassium nitrate solution needed to add to 200 liters of distilled water to achieve a nitrate concentration of 2 ppm, we can use the following formula:
Volume of KNO3 solution needed = (target concentration * volume of water) / concentration of KNO3 solution
Plugging in the values:
Volume of KNO3 solution needed = (2 ppm * 200 L) / 247000 ppm = 0.00162 L or 1.62 mL
Therefore, you would need to add 1.62 mL of the potassium nitrate solution to 200 liters of distilled water to achieve a nitrate concentration of 2 ppm.
Thanks